A Chemist Has a Solution of 65
Liters of 25 hydrochloric acid solution. So we have x 170 and y 1700.
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Theresa Morgan a chemist has a 25 hydrochloric acid solution and a 65 hydrochloric acid solution.
. Y 1700. Just taking percent solution times the volume of the total volume. A chemist has one solution which is 50 acid and a second which is 25 acid.
A chemist has a solution that is 20 hydrochloric acid hcl and a solution that is 50 hcl. 025100 x 070x 060 100. How many liters of each should she mix to get 4375 liters of a hydrochloric acid solution with a 45 acid concentration.
How much of each should be mixed to make 10 litres of 40 acid solution. And why for the 65 solution. How many gallons of each will make 350 gallons of 55.
How many gallons of each will make 600 gallons of 72 pure acid. A chemist adds 650 mL of a 0258 molL copperII sulfate CuSO4 solution to a reaction flask. Mass of acid in 25 Mass of acid in 70 Mass of acid in 60.
Find how many milliliters of each that should be mixed to get the desired solution. The chemist must drain 78 g of the 25 acid and replace it with 78 g of 70 acid. To determine the concentration of the solution of sulfuric acid the chemist should perform titration with the use of 10 M NaOH.
25 025x 070x 60. Okay so these are these are the volumes that we have. X 35 045 78.
This is the answer in the space provided. Liters of 65 hydrochloric acid solution. Solution for A chemist needs 60 milliliters of a solution that is 45 acid but has only 35 and 65 solutions available.
Well we know that 03 X. A chemist has 70 mL of a 50 methane solution. Amount Part Total Start 70 05 Add x 08 Final Setupthemixturetable.
The operating equation is. We will start with one vari-able problems. Solve the problemA chemist needs 70 milliliters of a 65 solution but has only 59 and 73 solutions available.
How many liters of each should she mix to get 1440 liters of a hydrochloric acid solution with a 60 acid concentration. Substituting y 1700 in 2 x 1700 1870. PLSSSS PSL PLS PLS HELP Theresa Morgan a chemist has a 30 hydrochloric acid solution and a 55 hydrochloric acid solution.
04 times the 14 leaders. X 1870 - 1700. A chemist has a solution of 65 pure acid and another solution of 30 pure acid.
We can conclude that 170 liters of 10 hydrochloric acid must be mixed with 1700 liters of 65 hydrochloric acid solution to. These problems can have either one or two variables. Answer by addingup3677 Show Source.
How much of a 80 solution must she add so the final solution is 60 methane. Amount of the 70 solution --- x L amount of the 45 solution--- 300-x L70x 45300-x 65300 time 100 70x 45300-x 65300 70x 13500 - 45x 19500 25x 6000 x 240 So 240 L of the 70 stuff and 60 L of the 45 stuff check7240 4560 19565300 195 looks good to me. Because 30 as a decimal is 03 was 065.
Calculate the mass in grams of copperII sulfate the chemist has added to the flask. The 10 M NaOH is suitable in the titration because it is a base which is used in titration in order to determine the unknown concentration. Y Because 65 as a decimal 65 is going to be equal to The 40.
How much of each solution should be mixed to obtain 300 cubic centimeters cc of a solution that is 30 hcl. Westartwith70 but dontknowhowmuchweadd. Algebra Systems of Equations and.
You can put this solution on YOUR website5x 8600 - x 72600. Find how many milliliters of each that should be. So then what do we know.
A chemist has a solution of 50 pure acid and another of 80 pure acid. How many milliliters of each should be.
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